Question

Two different floor plans are being offered in a new housing development. Several prospective
buyers from three different age groups were surveyed about which plan they preferred. Find
the probability that a randomly selected buyer preferred Plan A or was in the 40-to 49-year-
old age group
Plan B
Plan A
20-29
30-3912
40-4916

Answer 1

Answer:

0.912

Step-by-step explanation:

The complete question is attached.

"OR" in probability means "ADDITION". So we find the individual probabilities and "ADD" them.

P(Plan A) would be the total people for plan A (add up column of Plan A) divided by total number of people [add up all the numbers].

Looking at the table, we have:

P (Plan A) = 38/68

Now,

P(40-49 Group) can be found by adding up the row of 40-49 age group and dividing by the total. So, we have:

P(40 - 49 Group) = 24/68

Now, adding up both:

38/68 + 24/68 = 62/68 = 0.912

Answer 2

Answer: 0.676

Step-by-step explanation: