The function f(t) = 4t2 − 8t + 6 shows the height from the ground f(t), in meters, of a roller coaster car at different times t. Write f(t) in the vertex form a(x − h)2 + k, where a, h, and k are integers, and interpret the vertex of f(t).

f(t) = 4(t − 1)2 + 3; the minimum height of the roller coaster is 3 meters from the ground
f(t) = 4(t − 1)2 + 3; the minimum height of the roller coaster is 1 meter from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 1 meter from the ground

Respuesta :

Answer:

The correct option is 3.

Step-by-step explanation:

The vertex form of a parabola is

[tex]f(x)=a(x-h)^2+k[/tex]            .... (1)

where a, h, and k are integers, and interpret the vertex of f(t). (h,k) is the vertex of the parabola.

The given function is

[tex]f(x)=4t^2-8t+6[/tex]

It can be written as

[tex]f(x)=4(t^2-2t)+6[/tex]

If an expression is defined as [tex]x^2+bx[/tex], then we need to add [tex](\frac{b}{2})^2[/tex] to make it perfect square.

In the expression [tex]t^2-2t[/tex] the value of b is -2. So, we nned to add and subtract [tex](\frac{-2}{2})^2[/tex] in the parenthesis.

[tex]f(x)=4(t^2-2t+1^2-1^2)+6[/tex]

[tex]f(x)=4(t^2-2t+1)+4(-1)+6[/tex]

[tex]f(x)=4(t-1)^2-4+6[/tex]

[tex]f(x)=4(t-1)^2+2[/tex]                .... (2)

The vertex form of the parabola is [tex]f(x)=4(t-1)^2+2[/tex].

From (1) and (2), we get h=1 and k=2. It means the vertex of the parabola is (1,2). Vertex of upward parabola is point of minima. So the  minimum height of the roller coaster is 2 meters from the ground.

Therefore the correct option is 3.

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