Question

The roots of the function f(x) = x2 – 2x – 3 are shown. What is the missing number?

x = –1 and x =

Answer 1

If you would like to find the roots of the function f(x) = x^2 - 2 * x - 3, you can calculate this using the following steps:

f(x) = x^2 - 2 * x - 3 = (x - 3) * (x + 1)
1. x = - 1
2. x = 3

The missing number would be 3.

Answer 2

The missing value is 3 because roots of the function f(x) = x2 – 2x – 3 are -1 and 3

What is a quadratic equation ?

Any equation of the form $\rm ax^2+bx+c=0$  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}$

We have a function:

f(x) = x² – 2x – 3

Equate the function to zero;

f(x) = 0

x² – 2x – 3 = 0

a = 1, b = -2, c = -3

$\rm x = \dfrac{-(-2) \pm\sqrt{-2^2-4(1)(-3)}}{2(1)}$

After simplification:

$\rm x = \dfrac{2 \pm\sqrt{16}}{2}$

x = 3  or x = -1

Thus, the missing value is 3 because roots of the function f(x) = x2 – 2x – 3 are -1 and 3

Learn more about quadratic equations here:

brainly.com/question/2263981

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