Question

A bathtub is draining at a constant rate. After 2 minutes, it holds 30 gallons of water. Three minutes later, it holds 12 gallons of water. Write an equation that represents the number yy of gallons of water in the tub after xx minutes. $y=$y=

Answer 1

original-amount drained after  2 minutes=30
original- amount drained after 5 minutes=12

5-2=3
30-12=18
therefor
3 minutes=18 gallons drained
divide 3
1minute=s6 gallons draine

find original
30+2mins=origninal
30+2*6=original
30+12=original=42

so
y=42-6x