Answer:
The sum of all whole numbers from 1 to 1000 is 500500
Solution:
The sum of “n” whole numbers is given as,
[tex]Sum = \bold{\frac{n(n + 1)}{2}}[/tex] ---- eqn 1
Where “n” represents the total number of terms.
Given that we have to find the sum of all whole numbers from 1 to 1000. This can be written as,
Sum of { 1,2,3,……….., 1000}
So here, total number of terms “n” = 1000.
By using equation 1, we can find the sum as,
Sum = [tex]\frac{1000(1000 + 1)}{2}[/tex]
[tex]= \frac{1000(1001)}{2}[/tex]
= 500(1001)
= 500500
Hence the sum of all whole numbers from 1 to 1000 is 500500