Answer: [tex]\dfrac{1}{3}[/tex]
Step-by-step explanation:
From he given table,
Types of legs ( blue , red , black) = 3
Number of legs other than blue = 3-1=2
Types of body (red and blue) = 2
Probability that LEGO figure does NOT have blue legs :-
[tex]\text{P(not blue legs)}=\dfrac{\text{Legs other than blue}}{\text{Total types of legs}}\\\\=\dfrac{2}{3}[/tex]
Similarly, Probability that LEGO figure has a red body :-
[tex]\text{P(red body)}=\dfrac{1}{2}[/tex]
Since both the events are independent , then
Then probability that the LEGO figure does NOT have blue legs but has a red body will be :-
[tex]\text{P(not blue legs and red body)=P(not blue legs) x P(red body)}\\\\=\dfrac{2}{3}\times\dfrac{1}{2}=\dfrac{1}{3}[/tex]
Hence, the correct answer is [tex]\dfrac{1}{3}[/tex] .