The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force. This is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k, is a very large number
Answer: The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force.
Explanation:
We know that the universal formula for the estimation of gravitational force is,
[tex]F=G \times\left(\frac{m_{1} \times m_{2}}{r^{2}}\right)[/tex]
Where,
F, Gravitational force, [tex]m_{1} \text { and } m_{2}[/tex]- objects masses r- The relative distance between the two objects
G, Gravitational Constant [tex]6.67 \times 10^{-11} \frac{N m^{2}}{k g^{2}}[/tex]
And, the electrostatic force between two scalar charges according to the Coulomb’s law is,
[tex]F=k \times\left(\frac{q_{1} \times q_{2}}{r^{2}}\right)[/tex]
F, Electrostatic force between two charges,[tex]q_{1} \text { and } q_{2}[/tex]- Two scalar charges, r - The relative distance between two scalar charges, k- Coulomb’s constant [tex]8.987 \times 10^{9} \frac{N m^{2}}{c^{2}}[/tex]
Now, on comparing the values of G and k, we can easily evaluate that eventually, the gravitational force will be lesser than the coulomb’s force.
Besides this, we can also judge this fact through various examples such as, a balloon rubbed with a cloth, easily sticks to the wall for some time. Opposing the gravitational force of the Earth which is not the case with the normal balloon.
It drops without having the electrostatic force between the wall and the balloon. This shows that the gravitational force draws lesser impact on objects as compared to the electrostatic force.
Answer: The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force.
Explanation: Edge
