When 50 grams of potassium chloride KCI is dissolved in 100 grams of water at 50 C the solution can correctly be described as
A unsaturated
B saturated
C supersaturated

Respuesta :

Answer: C supersaturated

Explanation:

Chemically speaking, a solution has two components: solute and solvent.  

The solute is that substance that dissolves in a liquid substance and its proportion in the resulting solution is usually less than the solvent.  

The solvent is the substance used to dissolve the solute, and generally its proportion in the resulting solution is greater. Being the most common used solvent water.

So, in this case the solute is potassium chloride (KCI) and the solvent is water.

On the other hand, in the attached figure we can observe the solubility vs temperature graph for KCI. As we can see the solubility of 50 grams of KCl in 100 grams of water is considered saturated (it contains the maximum amount of solute dissolved in solvent at this temperature) at [tex]80\°C[/tex].

However, this 50 grams of KCl are dissolved in 100 grams of water at [tex]50\°C[/tex], which means the solute limit the solvent is able to admit has passed.

In other words: there is an excess of solute, hence the solution is supersaturated .

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