Respuesta :

Answer:

The answer to your question is: 12 ml of HCl

Explanation:

Data

Na2CO3   V = 30 ml   [  ] = 0.1 mol/l

HCl = 0.5 mol /L   V = ?

Balance reaction

                Na₂CO₃   + 2HCl    ⇒    2NaCl   +   CO₂     + H₂O

Process

1.- Find the number of moles of Na2CO3

Molarity = n / V

 n = VM                      n = (30)(0.1) = 3 moles

2.- From the reaction

                             1 mol of Na2CO3 --------------- 2 HCl

                             3 mol -------------------------------  x

                             x = (3 x 2) / 1

                            x = 6 moles of HCl

3.- Volume of HCl

     V = n / M            V = 6 / 0.5  

                                V = 12 ml              

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