Respuesta :

Answer:

The volume for a piece of gold that has the mass of 318,67 g is 16,50cm3

Explanation:

Density = mass / volume

Volume = mass/ density

Volume = 318,97 g / 19,32 g/cm3 = 16,50cm3

Answer:

The volume of a gold piece  is[tex]V=16.51 \mathrm{cm}^{3}[/tex]

Explanation:

Given:

Density of  pure gold,  [tex]D=19.32 \frac{g}{\mathrm{cm}^{3}  }[/tex]

Mass of the gold piece, [tex]\mathrm{M}=318.97[/tex]

To Find:

The volume for a piece of gold whose mass is  [tex]318.97 g[/tex]

Solution:

The formula for density is:

[tex]D=\frac{M}{V}[/tex]

where,

D is density,

M is mass,  

V is volume.

The above formula can be rewriiten as

[tex]V=\frac{M}{D}[/tex]

Substituting the values ,we get

[tex]V=318.97 \mathrm{g} \frac{\mathrm{Au}}{19.32 \frac{\mathrm{g}}{\mathrm{cm}^{3}} \mathrm{Au}}[/tex]

Taking multiplicative inverse of density , we have

[tex]V=318.97 \text { of }Au\frac{1 \mathrm{cm}^{3}\mathrm{Au}}{19.32 \mathrm{of}\mathrm{Au}}[/tex]

[tex]V=318.97\frac{1 \mathrm{cm}^{3}}{19.32}[/tex]

[tex]V=\frac{318.97}{19.32} \mathrm{cm}^{3}[/tex]

[tex]V=16.51 \mathrm{cm}^{3} \mathrm{Au}[/tex]

Result:

Thus the volume of gold piece weighing 318.97 g is[tex]V=16.51 \mathrm{cm}^{3}[/tex]

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