A strip of AISI 304 stainless steel, 2mm thick by 3cm wide, at 550°C, continuously enters a cooling chamber that removes heat at a rate of 120 kW. How fast must it move to achieve a temperature of 140 °C at the exit?

Respuesta :

Answer:

V = 1.23 m/s

Explanation:

Given data:

AISI 304 steel

thickness of steel = 2 mm

width  =  3 cm

Temperature =  550 degree celcius

wer know that heat is given as Q  

[tex] Q = m\times Cp \Delta T[/tex]

[tex]\Delta T = 550 - 140 = 410 \degree\ celcius[/tex]

for AISI 304 steel Cp is 502 J/kg . K

We know that

[tex]\dot mass  =\rho A V[/tex]

[tex]\rho = 7.9\times 10^3 kg/m^3[/tex]

[tex]A = 2\times 10^{-3} \times 3\times 10^{-2} m^2[/tex]

therefore VELOCITY V  will be

[tex]120\times 10^{3} = 7.9\times 10^{3} \times 6\times 10^{-5} \times V\times 502\times 410[/tex]

solving for V we get

V = 1.23 m/s

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