Answer:
V = 1.23 m/s
Explanation:
Given data:
AISI 304 steel
thickness of steel = 2 mm
width = 3 cm
Temperature = 550 degree celcius
wer know that heat is given as Q
[tex] Q = m\times Cp \Delta T[/tex]
[tex]\Delta T = 550 - 140 = 410 \degree\ celcius[/tex]
for AISI 304 steel Cp is 502 J/kg . K
We know that
[tex]\dot mass =\rho A V[/tex]
[tex]\rho = 7.9\times 10^3 kg/m^3[/tex]
[tex]A = 2\times 10^{-3} \times 3\times 10^{-2} m^2[/tex]
therefore VELOCITY V will be
[tex]120\times 10^{3} = 7.9\times 10^{3} \times 6\times 10^{-5} \times V\times 502\times 410[/tex]
solving for V we get
V = 1.23 m/s