Question

A hydraulic cylinder must be able to exert a force of 38.8kN. The piston diameter is 30 mm. Computer the required pressure in the oil.

Answer 1

Answer:

Pressure in the oil is 54.89 Mpa

Explanation:

Pressure is the ration of force applied to the perpendicular area. Pressure is uniform and perpendicular to surface.

Step1

Given:

Diameter of the piston is 30 mm.

Force exert is 38.8 kN.

Calculation:

Step2

Expression for pressure in the oil is expressed as follows:

$P=\frac{F}{A}$

Here, P is the pressure, A is the normal surface area and F is the exerted force on the piston.

Substitute the values in the above equation as follows:

$P=\frac{F}{\frac{\pi}{4}d^{2}}$

$P=\frac{38.8\times1000}{\frac{\pi}{4} ((30mm)(\frac{1m}{1000mm}))^{2} }$

$P = 54.89\times10^{6}$ pa.

Or,

P = 54.89 Mpa.

Thus, the pressure in the oil is 54.89 Mpa.

Answer 2

Based on the calculations, the required pressure in this oil is equal to $54.9 \times 10^6 \;N/m^2$

Given the following data:

Force = 38.8 kN.

Diameter = 30 mm to m = 0.03 m.

What is pressure?

Pressure can be defined as a measure of the force exerted per unit area of an object or physical body. Thus, it is usually measured in Newton per meter square and calculated by using this formula:

$P = \frac{F}{A}$

Where:

• P is the pressure.

• F is the force.

• A is the area.

For the area:

$A =\frac{\pi d^2}{4} \\\\A=\frac{3.142 \times 0.03^2 }{4} \\\\A=0.000707\;m^2$

Now, we can determine the pressure:

$P=\frac{38.8 \times 10^3}{0.000707}$

$P = 54.9 \times 10^6 \;N/m^2$

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