Question

A 68 kg hiker walks at 5.0 km/h up a 3% slope. The indicated incline is the ratio of the vertical distance and the horizontal distance expressed as percentage.

What is the necessary metabolic power?

Answer 1

Answer:

$P = 27.8 Watt$

Explanation:

As we know that the slope of the inclination is 3%

so we can say that

$tan\theta = 0.03$

since it is very small so here we can take approximation as

$tan\theta = sin\theta = 0.03$

so we need to find the metabolic power which is given as

$P = F. v$

so here we have

$F = mg sin\theta$

$v = 5 km/h = 1.39 m/s$

now we have

$P = (68)(9.81)(0.03)(1.39)$

$P = 27.8 Watt$