Answer:
v = 0.92 c
Explanation:
Let the actual length of the rod is L
now its two components along X and Y direction is given as
[tex]L_x = Lcos55[/tex]
[tex]L_y = Lsin55[/tex]
now by the concept of relativity we know that
[tex]L_x' = L_x\sqrt{1 - \frac{v^2}{c^2}}[/tex]
so along x direction the length will contract
now the angle observed by the observer is given as
[tex]tan\theta' = \frac{L_y}{L_x'}[/tex]
[tex]tan75 = \frac{L_o sin55}{L_ocos55\sqrt{1 - \frac{v^2}{c^2}}}[/tex]
[tex]3.73 = \frac{1.43}{\sqrt{1 - \frac{v^2}{c^2}}}[/tex]
[tex]\sqrt{1 - \frac{v^2}{c^2}} = 0.38[/tex]
[tex]v = 0.92 c[/tex]