Question

A pipe with a diameter of 2 cm is attached to a garden hose with a nozzle. If the velocity of how in the pipe is 2 m/s. what is the velocity of the flow at the nozzle when it is adjusted to have a diameter of 4 mm?

Answer 1

Answer:

velocity at nozzle is given as

$v_2 = 50 m/s$

Explanation:

As we know that volume flow rate through the pipe is always constant

so we can say that volume flow rate is given as

$Q = \frac{dV}{dt}$

$Q = area \times speed$

so we will have

$A_1 v_1 = A_2v_2$

here we have

$A_1 = \pi r_1^2$

$A_2 = \pi r_2^2$

now we have

$\pi (2^2) 2 m/s = \pi (0.4)^2 v_2$

$v_2 = 50 m/s$