Explanation:
Given
Refractive Index [tex](n_1)=1.65[/tex]
[tex]n_2=1.35[/tex]
angle of incident[tex]=35 ^{\circ}[/tex]
Light originates in the medium of higher refractive index
Let [tex]\theta _1[/tex] and [tex]\theta _2 [/tex]be the incident and refraction angles respectively thus according to snell's law
[tex]n_1sin\theta _1=n_2sin\theta _2[/tex]
[tex]1.65\times sin35=1.35\times sin\theta _2[/tex]
[tex]sin\theta _2=0.701[/tex]
[tex]\theta _2=44.507^{\circ}[/tex]
(b)Ray originates from lighter medium
[tex]1.35\times sin35=1.65\times sin\theta _2'[/tex]
[tex]sin\theta _2'=0.469[/tex]
[tex]\theta _2'=27.96\approx 28^{\circ}[/tex]