Question

How many electrons would have to be removed from a coin to leave it with a charge of +1.5 × 10^-5 C?

Answer 1

Answer:

$9.375\times 10^{13}electron$ leave out with a charge of $1.5\times 10^{-5}C$

Explanation:

We have given total charge $Q=1.5\times 10^{-5}C$

We know that charge on one electron = $1.6\times 10^{-19}C$

We have to find the total number of electron in total charge

So $q=ne$, here q is total charge, n is number of electron and e is charge on one electron

So $1.5\times 10^{-5}=n\times 1.6\times 10^{-19}$

$n=0.9375\times 10^{14}=9.375\times 10^{13}electron$

So $9.375\times 10^{13}electron$ leave out with a charge of $1.5\times 10^{-5}C$