You can use the fact that a closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle.
Option A: [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex]correct choice since the line segment QP is and line segment SR are congruent.
Given that:
- Angles PTQ and STR are vertical angle and congruent.
- Circle T(centered at T).
- Line segments TP, TQ, TR, and TS are radii.
How to find which lines are intersecting?
Since angle PTQ and angle STR are congruent, thus we have:
PR and SQ as straight intersecting lines.
Due to angle PTS and angle QTR are opposite angles made by intersecting lines, we have them as congruent or say of equal measurement.
[tex]\angle PTS \cong \angle QTR[/tex]
Since [tex]\overline{TP} = \overline{TQ} = \overline{TR} = \overline{TS}[/tex], thus we have got:
[tex]\overline{PR} = \overline{SQ}[/tex] in measurement ( as PR is sum of PT and TR and same for SQ)
How is a rectangle made?
"A closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle", we have PQRS as a rectangle.
As a rectangle have opposite sides parallel and equal, we have got:
[tex]\overline{PQ} \cong \overline{SR}[/tex]
Thus, Option A: [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex] is the correct choice since the line segment QP is and line segment SR are congruent.
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