Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present age. What are their present ages ?

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corm

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

[tex]M = 6S[/tex]

[tex]S + 5 = \frac{1}{3}M[/tex]

where [tex]S[/tex] is the current age of Shobos and [tex]M[/tex] is the current age of his mother.

Substituting the first equation into the second will allow us to solve for [tex]S[/tex]:

[tex]S + 5 = \frac{1}{3}M[/tex]

[tex]S + 5 = \frac{1}{3}(6S)[/tex]

[tex]S + 5 = 2S[/tex]

[tex]S = 5[/tex]

Substituting this value into the first equation gives us the age of the mother:

[tex]M = 6S[/tex]

[tex]M = 6(5)[/tex]

[tex]M = 30[/tex]

Answer:

Present age of Shobo is 5 years and present age of Shobo's mother is 30 years.

Step-by-step explanation:

Given :-

  • Shobo's mother's present age is 6 times of Shobo's present age.
  • Shobo's age 5 from now will be 1/3 of his mother's present age.

To find :-

  • Their present ages.

Solution :-

Consider,

  • Shobo's present age = x years

Shobo's mother's present age is 6 times of Shobo's present age.

  • Shobo's Mother's Present age = 6x years

Shobo's age 5 from now,

= (x+5) years

According to the question ,

[tex]\to\sf{x+5=\dfrac{1}{3}\times\:6x}[/tex]

→ x + 5 = 2x

→ x-2x = -5

→ -x = -5

→ x = 5

Shobo's present age = 5 years

Shobo's mother's present age = 6×5 = 30 years.

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