Question

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select three options. y = –Two-fifthsx – 2 2x + 5y = −10 2x − 5y = −10 y + 4 = –Two-fifths(x – 5) y – 4 = Five-halves(x + 5)

Answer 1

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$.

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

$5x - 2y = -6$

$-2y = -5x - 6$

$y = \frac{5}{2}x + 3$

We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$. With this, we have the following equation for our new line:

$y = \frac{-2}{5}x + C$

where $C$ is the Y-intercept that we now need to determine with the coordinates given in the problem statement, $(5, -4)$:

$y = \frac{-2}{5}x + C$

$(-4) = \frac{-2}{5}(5) + C$

$-4 = -2 + C$

$C = -2$

Finally, we can create our line:

$y = \frac{-2}{5}x - 2$

$5y = -2x - 10$

$2x + 5y = -10$