One gallon of pure isooctane is about 230 moles. How many moles of O2 would be required to completely combust one gallon of isooctane?

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Answer:

Explanation:

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At first, consider the balanced reaction for the combustion of the isooctane:

[tex]C_8H_{18}+\frac{25}{2} O_2-->8CO_2+9H_2O[/tex]

Now, the stoichiometric relationship between the hydrocarbon and the oxygen leads to:

[tex]molO_2=230molC_8H_{18}(\frac{\frac{25}{2}mol O_2 }{1mol C_8H_{18}} )=2875molO_2[/tex]

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