Answer:
[tex]m_{HClO_3}=12.7gHClO_3[/tex]
Explanation:
Hello,
Considering the reaction:
[tex]3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3[/tex]
The molar masses of chlorine and chloric acid are:
[tex]M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol[/tex]
Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:
[tex]m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3[/tex]
Best regards.