According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams of chlorine gas? 3 C12(g) + 3 H2O(1) ► 5 HCl(aq) + HCO3(aq) grams HC103

Respuesta :

Answer:

[tex]m_{HClO_3}=12.7gHClO_3[/tex]

Explanation:

Hello,

Considering the reaction:

[tex]3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3[/tex]

The molar masses of chlorine and chloric acid are:

[tex]M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol[/tex]

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

[tex]m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3[/tex]

Best regards.

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