Write an equation of the line that passes through points (3, 7) and (5, 11).
A. y – 7 = 5(x – 3)
B. y – 7 = 2(x – 3)
C. y + 7 = 5(x – 3)
D. y + 7 = 2(x + 3)
You have to first solve for the slop using the equation y2-y1/x2-x1 and then you plug the slope (m) into y=mx+b using one of the x and y values from any of the points above and then lastly solve for b.
For these particular points it would look like this... 11-7/5-3 =2 (slope/m) 7=2(3)+b 7=6+b 7-6=b 1=b Final equation: y=2x+1
