Question

Will mark the brainliest! Which system of linear inequalities is graphed?




{x≤−3y≤−x−3

{x<−2y≤−x−1

{x<−3y≤−x−1

{x<−3y≤−x+1

Answer 1

Hey!

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Steps To Solve:

~Coordinates of the line

(0, -1) and (-1, 0)

~Find slope

$m = \frac{0 - (-1)}{-1 - 0} = \frac{1}{-1} = -1$

~Find the equation of the line

y = mx + b

m = slope

b = y-intercept

m = -1 or -x

b = -1

y = -x - 1

~Check using zero rule (substitute x and y for (0, 0))

y = 0 - 1

y = -1 (Correct)

0 = -x - 1

-x = 1 - 0

-x = 1 (Incorrect)

~Check

{x<−3y≤−x−1

0 < -3(0) ≤ 0 - 1

0 < 0 ≤ -1

*Note* Since the line isn't near the origin, the points (0, 0) don't satisfy the equation.

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Answer:

{x<−3y≤−x−1

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Hope This Helped! Good Luck!