Respuesta :

javh10

being [tex]x^{2} +5x+6[/tex] the answer is (x-3)(x-2)

begin [tex]x^{2} -5x+6[/tex] the answer is (x+3)(x+2)

1. [tex]x^{2} +5x+6[/tex]

second grade formala is used

[tex]x= \frac{-b±\sqrt{b^{2} } -4ac}{2a}\\ x=\frac{-5±\sqrt{5^{2} } -4.1.6}{2} \\ x= \frac{-5±1}{2} \\ x_{1} =-3  \\  x_{2} =-2[/tex]

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