being [tex]x^{2} +5x+6[/tex] the answer is (x-3)(x-2)
begin [tex]x^{2} -5x+6[/tex] the answer is (x+3)(x+2)
1. [tex]x^{2} +5x+6[/tex]
second grade formala is used
[tex]x= \frac{-b±\sqrt{b^{2} } -4ac}{2a}\\ x=\frac{-5±\sqrt{5^{2} } -4.1.6}{2} \\ x= \frac{-5±1}{2} \\ x_{1} =-3 \\ x_{2} =-2[/tex]