Answer:[tex]5k^2+6k[/tex]
Explanation:
Given
initial side of cube is k cm
New dimensions are
k+2 cm
k+3 cm
k cm
[tex]V_{initial}=k^3[/tex]
[tex]V_{Final}=\left ( k+3\right )\left ( k+2\right )\left ( k\right )[/tex]
Now [tex]V_{final}-V{initial}=\left ( k+3\right )\left ( k+2\right )\left ( k\right )-k^3[/tex]
[tex]\Delta V=k^3+5k^2+6k-k^3=5k^2+6k[/tex]