Question

Instructions for a chemical procedure state to mix salt, baking soda, and water in a 20:15:10 ratio by mass. How many grams of water would be required to make a mixture that contains 24 grams of baking soda?

Answer 1

Answer:

16 g of water.

Step-by-step explanation:

salt : baking soda : water =  20 : 15 : 10

If we have  24 g of baking soda that is 24/15 = 8/5 times of 15.

So by proportion the amount of water would be 10 * 8/5 = 16 grams.

Answer 2

The mass of water in the mixture is 16 gm

What is Ratio and Proportion ?

When a number is divisible by another number then they can be written in the form of ratio p :q , When two ratios are equal they are said to be in proportion.

It is given that

salt, baking soda, and water in a 20:15:10 ratio by mass are mixed

mixture contains 24 grams of baking soda

Mass of Water = ?

Baking Soda : Water = 15 : 10

Let the mass of water is x

then the ratio is 24 : x

As both these ratios are equal

15 : 10 = 24 : x

15 / 10 = 24 / x

x = 24 * 10 / 15

x = 16 gm

Therefore the mass of water in the mixture is 16 gm.

To know more about Ratio and Proportion

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