Question

What is the equation of a line perpendicular to 3x +4y=16 and passes through the point (0-5)

Answer 1

Answer:

y = 4/3x - 5

Explanation:

First, change 3x + 4y = 16 to y = mx+b form

3x+4y=16

4y=-3x+16

y = -3/4x + 4

Now, to make it perpendicular, flip the slope and multiply be negative 1

You get 4/3 as your slope

You have you y-intercept, (0, -5), so now you can get your equation

It will be y = 4/3x - 5