Answer:
given,
Probability of student studying math P(M)=[tex]\dfrac{45}{100} = 0.45[/tex]
Probability of student studying physicsP(P) = [tex]\dfrac{61}{100} = 0.61[/tex]
Probability of student studying both math and physics together P(M∩P) = [tex]\dfrac{25}{100} = 0.25[/tex]
a) student took mathematics or physics
P(M∪P) = P(M) + P(P) - P(M∩P)
= 0.45 + 0.61 - 0.25
= 0.81
b) student did not take either of the subject
P((M∪P)') = 1 - 0.81
= 0.19
c) Student take physics but not mathematics
P(P∩M') = P(P) - P(P∩M)
= 0.61 - 0.25
= 0.36
studying physics and mathematics is not mutually exclusive because we can study both the subjects.