Answer:
The answer to your question is: 4.5 %
Explanation:
0.126 moles of AgNO3
mass percent = ?
mass of water = 475 g
Formula
weight percent = weight of solute / weight of solution x 100
Weight of solute
MW AgNO3 = 108 + 14 + (16 x 3)
= 108 + 14 + 48
= 170 g
170 g of AgNO3 ------------------- 1 mol
x --------------------- 0.126 moles
x = (0.126 x 170) / 1 = 21.42 g of AgNO3
Weight percent = 21.42/475 x 100
= 4.5 %