Answer:
x = 2 , y = -3
Step-by-step explanation:
Solve the following system:
{6 x + 2 y = 6 | (equation 1)
7 x + 3 y = 5 | (equation 2)
Swap equation 1 with equation 2:
{7 x + 3 y = 5 | (equation 1)
6 x + 2 y = 6 | (equation 2)
Subtract 6/7 × (equation 1) from equation 2:
{7 x + 3 y = 5 | (equation 1)
0 x - (4 y)/7 = 12/7 | (equation 2)
Multiply equation 2 by 7/4:
{7 x + 3 y = 5 | (equation 1)
0 x - y = 3 | (equation 2)
Multiply equation 2 by -1:
{7 x + 3 y = 5 | (equation 1)
0 x+y = -3 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 14 | (equation 1)
0 x+y = -3 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 2 | (equation 1)
0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 2 , y = -3
