Question

If the force on the tympanic membrane (eardrum) increases by about 1.50 above the force from atmospheric pressure, the membrane can be damaged.When you go scuba diving in the ocean, below what depth could damage to your eardrum start to occur? The eardrum is typically 8.20 in diameter. Take the density of seawater to be equal1.03*10^3 kg/m^3.

Answer 1

Answer:

15 m

Explanation:

Pressure = 1.5 times atmospheric pressure

Atmospheric pressure = 1.01 x 10^5 Pa

So, Pressure, P = 1.5 x 1.01 x 10^5 = 1.515 x 10^5 Pa

Diameter = 8.2 mm

radius = 8.2 /2 = 4.1 mm = 4.1 x 10^-3 m

density, d = 1.03 x 10^3 kg/m^3

Pressure = h x d x g

Where, h is the depth, d be the density of sea water and g be the acceleration due to gravity

1.515 x 10^5 = h x 1.03 x 10^3 x 9.8

h = 15 m

Thus, you can go upto depth of 15 m for the safe diving.

Answer 2

Answer:

Depth will be 15 m

Explanation:

We have given pressure is 1.5 times of atmospheric pressure

We know that atmospheric pressure is $1.01\times 10^5Pa$

So pressure will be $P=1.5\times 1.01\times 10^5=1.515\times 10^5Pa$

Density of sea water $\rho =1.03\times 10^3kg/m^3$

We have to find the depth of sea that is height h

We know that pressure is given by

$P=h\rho g$

So $1.515\times 10^5=h\times 1.03\times 10^3\times 9.8$

h = 15 m

So depth will be 15 m