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The area of a rectangle is 128 sq. ft. If the width is twice the length, what is the measure of the length of the rectangle?

Respuesta :

We calculate the area of ​​a rectangle with the equation

A = LW*1/2
A = 
The area of a rectangle
L = 
the height of the triangle
W = the base of the triangle

If the equation is one unknown to solve them quickly .
A = 128sq.ft
L = ?
W = 2L

substitute values ​​into the formula

A = L * W *1/2
128sq.ft = Lft. * (2Lft) *1/2
128 = L
²
L = √128 = 8√2

W = 2L = 2*8
√2 = 16√2





DGC
Length is 8 and width is 16. I hope this helps!
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