Question

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = y minus 3 equals StartFraction one-half EndFraction left-parenthesis x minus 1 right-parenthesis.(x – 1). What is the slope-intercept form of the equation for this line?

y = y equals StartFraction one-half EndFraction x plus 2.x + 2
y = y equals StartFraction one-half EndFraction x minus 4.x – 4
y = y equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction.x +
y = y equals StartFraction one-half EndFraction x minus StartFraction 7 Over 2 EndFraction.x –

Answer 1

Answer:

$y=\frac{1}{2}x+\frac{5}{2}$

Step-by-step explanation:

we have

$y-3=\frac{1}{2}(x-1)$

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

Distribute in the right side

$y-3=\frac{1}{2}x-\frac{1}{2}$

Adds 3 both sides

$y=\frac{1}{2}x-\frac{1}{2}+3$

$y=\frac{1}{2}x+\frac{5}{2}$

therefore

y = equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction

Answer 2

Answer:

C on edge

Step-by-step explanation: