Question

distance between -6.2 and -9.1
Step By Step

Answer 1

Answer:

$D=\sqrt{10}=3,16...$

Step-by-step explanation:

$A(x_{1},y_{1})$

$B(x_{2};y_{2})$

$D=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$A(-6,2)$

$B(-9;1)$

$D=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$D=\sqrt{[-9-(-6)]^{2}+(1-2)^{2}}$

$D=\sqrt{[-9+6]^{2}+(1-2)^{2}}$

$D=\sqrt{[-3]^{2}+(-1)^{2}}$

$D=\sqrt{9+1}$

$D=\sqrt{10}=3,16...$

Answer 2

Answer:

The distance between  -6.2 and -9.1 is 2.9.

Step-by-step explanation:

Given : Two numbers -6.2 and -9.1.

To find : What is the distance between the numbers ?

Solution :

Let A=-6.2

B=-9.1

The distance between two number is $d=|B-A|$

Substitute the values,

$d=|-9.1-(-6.2)|$

$d=|-9.1+6.2|$

$d=|-2.9|$

$d=2.9$

Therefore, The distance between  -6.2 and -9.1 is 2.9.