Answer:
[tex]Q= m \times c \times \Delta T[/tex]
where
[tex]\Delta T[/tex] = Final T - Initial T
Q is the heat energy in calories = 2.92 KJ = 2920 Joules
c is the specific heat capacity (for iron 0.450 J/(g℃))
m is the mass of water
Plugging in the values
[tex]2920J=m\times0.450 \frac {J}{(g^\circ{C})}\times(254^\circ{C}-72^\circ{C})[/tex]
[tex]2920J=m\times0.450 \frac {J}{(g^\circ{C})}\times(182^\circ{C})[/tex]
[tex]mass=\frac{2920 J}{0.450 \frac{J}{g^\circ{C}} \times 182^\circ{C}}[/tex]
mass = 35.6℃ is the Answer