Respuesta :

Answer:

[tex]Q= m \times c \times \Delta T[/tex]

where

[tex]\Delta T[/tex] = Final T - Initial T

Q is the heat energy in calories = 2.92 KJ = 2920 Joules

c is the specific heat capacity (for iron 0.450 J/(g℃))  

m is the mass of water

Plugging in the values  

[tex]2920J=m\times0.450 \frac {J}{(g^\circ{C})}\times(254^\circ{C}-72^\circ{C})[/tex]

[tex]2920J=m\times0.450 \frac {J}{(g^\circ{C})}\times(182^\circ{C})[/tex]

[tex]mass=\frac{2920 J}{0.450 \frac{J}{g^\circ{C}} \times 182^\circ{C}}[/tex]

mass = 35.6℃ is the Answer

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