The number of ways of choosing 1 soft drink from 6 soft drinks is 6C1 = 6!/((6-1)! * 1!) = 6!/(5!) = (6*5*4*3*2*1)/(5*4*3*2*1) = 6.
Similarly, the number of ways of choosing 1 fruit juice from 8 cans of juice is 8C1 = 8!/((8-1)! * 1!) = 8!/7! = 8
number of combinations of 1 soft drink AND 1 fruit drink = 6 x 8 = 48
Answer: D [48]