Respuesta :

Tareki
the approximate value of x = 0.92

Answer:

The approximate positive value of x is 0.92.

Step-by-step explanation:

Given,

[tex](x+5)^2 = 35[/tex]

[tex]x+5 = \pm \sqrt{35}[/tex]

[tex]x = \pm \sqrt{35}-5[/tex]

Thus,

[tex]x = \sqrt{35}-5[/tex] or [tex]x=-\sqrt{35}-5[/tex]

By taking positive value,

[tex]x = \sqrt{35}-5[/tex]

[tex]x=5.91607978 - 5 = 0.91607978\approx 0.92[/tex]

First option is correct.