Question

How many grams of NH3 can be produced from 4.54 mol of N2 and excess H2?

Answer 1

First we make a Balanced Chemical Equation:

$N_{2} + 3H_{2} = 2NH_{3}$


Now we can solve using the Mole Ratio:

4.54 mol N2 × 2 / 1 × 17.04 g/mol NH3 
= 154.72 g

If you need further clarification, feel free to comment.