Question

Which is the least valid way to stimulate how many boys and girls are in a random sample of 20 students from a school that is half boys and half girls?

A. Flip a coin 20 times, assigning one out come to boys and the other to girls

B. Drop 20 coin at once and count the number of each outcome

C. Count how many boys and girls are in your mat class and use a proportion

D. Have a calculator generate 20 random integers and count the number of even and odd integers

Answer 1

I think the answer is C

Answer 2

Total number of Student in the School in which half are boys and Half are girls =20

Probability of an event

             $=\frac{\text{Total favorable oucome}}{\text{Total Possible outcome}}$                  

Probability of Number of Boys as well as Probability of Number of Girls

                               $=\frac{10}{20}\\\\=\frac{1}{2}$  

The Most appropriate option is

Option C

Count how many boys and girls are in your math class and use a proportion.

In Option A, B and D

The probability of each outcome that is Success and Failure will be nearly equal to 0.50 .

But in Option C, you can't say precisely that Probability will be equal to , 0.50 in each case , that is Success and Failure.