The slope of the first line is [tex]m_1=\frac{-1}{3}[/tex]. To be perpendicular the slope of the second line must be the negative reciprocal of the first: [tex]m_2=3[/tex] Use the slope-intercept formula: [tex]y=mx+b[/tex] Substitute known values: [tex]12=3(3)+b[/tex] Solve for [tex]b[/tex]: [tex]b=3[/tex] Complete the formula: [tex]y=3x+3[/tex]