Answer:
Explanation:
To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:
[tex]F = k \frac{q_1 q_2}{d^2}[/tex]
where k is Coulomb's constant, [tex]q_1[/tex] and [tex]q_2[/tex] are the charges and d is the distance between the charges.
Working a little the equation, we can take:
[tex]d^2 = k \frac{q_1 q_2}{F}[/tex]
[tex]d = \sqrt{ k \frac{q_1 q_2}{F}}[/tex]
And this equation will give us the distance between the charges. Taking the values of the problem
[tex]k= 9.00 \ 10^9 \frac{N \ m^2}{C^2} \\q_1 = 165.0 \mu C \\q_2 = 115.0 C\\F=- 6.00[/tex]
(the force has a minus sign, as its attractive)
[tex]d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}[/tex]
[tex]d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}[/tex]
[tex]d = \sqrt{ 28,462,500 \ m^2}}[/tex]
[tex]d = 5,335.026 m[/tex]
And this is the distance between the charges.
