Answer:
[tex]t_{1/2}=0.175 s[/tex]
Explanation:
Hello,
At first, we must consider the rate law as:
[tex]\frac{1}{[NO_2]}=kt+ \frac{1}{[NO_2]_0}[/tex]
The supposition of half-life, leads to [tex][NO_2]=\frac{[NO_2]_0}{2} \\[/tex]
Thus, after the algebraic arrangement, we get:
[tex]t_{1/2}=\frac{1}{k[NO_2]_0} \\t_{1/2}=\frac{1}{(1.27x10^1\frac{L}{mol*s} )(0.45 \frac{mol}{L} )} \\\\t_{1/2}=0.175s[/tex]
Best regards