Answer:
[tex]\frac{dp}{dt}[/tex] = 0.05P - 150
Step-by-step explanation:
Let P(t) be the balance of the loan at time t years,
Let P(t) will satisfy [tex]\frac{dp}{dt}=rP-R[/tex]
where r = annual interest rate
R = per year payment rate
R = $150/year
r = [tex]\frac{5}{100}[/tex] = 0.05 [tex]\frac{5}{100}[/tex]
Now we have the following picture,
Interest Balance Payment
5% ⇒ P(t) ⇒ $150/year
(0.05)
Therefore, a linear ODE satisfied by P(t) is given by
[tex]\frac{dp}{dt}[/tex] = 0.05P - 150