Answer:
The answer to your question is: 639.6 g of NaH2PO4
Explanation:
Data
NaH2PO4 = ?
NaOH 36.29 ml of 0.250 M
MW Na2PO4 = (23 x 2) + (1 x 31) + (16 x 4) = 141 g
MW NaOH = (23 x 1) + (16 x 1) + (1 x 1) = 40 g
Molarity = # moles / volume
# moles = molarity x volume
# moles of NaOH = 0.25 x 36.29 = 9.07
1 mol of NaOH ------------------- 40 g
9.07 moles -------------------- x
x = 9.07 x 40 / 1 = 362.9 g of NaOH
NaH2PO4(s) + 2 NaOH(aq) → Na3PO4(aq) + 2 H20(1)
141 g of NaH2PO4 ----------------------- 2(40) g of NaOH
x ---------------------- 362.9 g of NaOH
x = 362.9 (141) / 80
x = 639.6 g of NaH2PO4
