Pasion wants to rent a car to take a trip and has a budget of $75. There is a fixed rental fee of $25 and a daily fee of $10. Write an inequality that would be used to solve for the maximum number of days for which Pasion can rent the car on her budget.

25x + 10 ≤ 75
25x + 10 ≥ 75
25 + 10x ≤ 75
25 + 10x ≥ 75

Respuesta :

Answer:

The answer is the 3rd one

Step-by-step explanation:

Answer:

The correct option is C) 25 + 10x ≤ 75

Step-by-step explanation:

Consider the provided information.

Pasion wants to rent a car to take a trip and has a budget of $75. There is a fixed rental fee of $25 and a daily fee of $10.

Let Pasion rent a car for x days and the daily fee is $10.

For x days Pasion needs to pay: $10x

Then the total cost will be:

[tex]25+10x[/tex]

But it is given that he can not spend more than $75.

That means he can spend only less than or equal to $70.

Thus, the required inequality is:

[tex]25+10x\leq 75[/tex]

Hence the correct option is C) 25 + 10x ≤ 75

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