Answer:
The kinetic energy of the mass at this height is 98,000 J.
Explanation:
The kinetic energy is defined as the energy exhibited by any moving object. It can be calculated as below
[tex]Kinetic \ energy= 1/2 \times mass \times (velocity)^2[/tex]
The mass of the object is given as 2000 Kg but the velocity acting on the object to raise it to 5 m distance is unknown.
Due to constant acceleration, we can use equations of motion to determine the velocity of the object at the distance of 5 m from the ground with the constant acceleration to be considered as [tex]-9.8 ms^-^2.[/tex]
The initial velocity can be determined using the equation of motion as
[tex]2as=v^2-u^2[/tex]
As a = [tex]-9.8 ms^-^2[/tex], [tex]s = 5 m, v = 0[/tex] , we have to determine u. This can be done as follows:
[tex]-2 \times 9.8 \times 5=0-u^2[/tex]
[tex]-98=-u^2[/tex]
[tex]u^2=98[/tex]
[tex]u=9.75 m/s[/tex]
Thus the velocity to determine the kinetic energy at 5 m distance is found as [tex]9.75 m/s[/tex].
The kinetic energy will be
Kinetic energy= [tex]1/2 \times 2000 \times 98=98000 J[/tex]
Thus the kinetic energy is 98,000 J.
