Question

s is the midpoint of line rt
r has the coordinates of (-10,2)
s has the coordinates of (6,4)
find the coordinates of endpoint t

Answer 1

Answer:

The coordinates of point t are (22,6)

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two point is equal to

$s=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

s(6,4)

(x1,y1)=r(-10,2)

Let

t(x2,y2)

substitute the values

$(6,4)=(\frac{-10+x2}{2},\frac{2+y2}{2})$

Solve for x2

$6=(-10+x2)/2\\12=-10+x2\\x2=12+10\\x2=22$

Solve for y2

$4=(2+y2)/2\\8=2+y2\\y2=8-2\\y2=6$

therefore

The coordinates of point t are (22,6)