Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
mass = 0.508 g, Volume = 0.175 L
Temperature = (25 + 273) K = 298 K, P = 1 atm
As per the ideal gas law, PV = nRT.
where, n = no. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
Hence, putting all the given values into the ideal gas equation as follows.
PV = [tex]\frac{mass}{\text{molar mass}} \times RT[/tex]
1 atm \times 0.175 L = [tex]\frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K[/tex]
= 71.02 g
As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of [tex]Cl_{2}[/tex] is 70.8 g/mol or 71 g/mol (approx).
Thus, we can conclude that the gas is most likely chlorine.