Question

An average man is requires about 2.00mg of fiboflavin (vitamin B2) per day. Cheese contains 5.5μg of riboflavin per gram of cheese. How many pounds of cheese would a man have to eat per day if this is his only source of riboflavin?

Answer 1

Answer:

0.8017 pounds

Explanation:

Considering,

1 μg = $10^{-6}\ g$

1 mg = $10^{-3}\ g$

Given that:

5.5 μg of the riboflavin is present in 1 g of cheese

Or,

$5.5\times 10^{-6}\ g$  of the riboflavin is present in 1 g of cheese

Requirement = 2.00 mg = $2\times 10^{-3}\ g$

So,

1 g of the riboflavin is present in $\frac {1}{5.5\times 10^{-6}}\ g$ of cheese

Thus,

$2\times 10^{-3}\ g$ of the riboflavin is present in $\frac {1}{5.5\times 10^{-6}}\times 2\times 10^{-3}\ g$ of cheese

Amount of cheese = 363.6364 g

Also,

1 g = $\frac {1}{453.592}\ pounds$

So,

Amount of cheese = $\frac {363.6364}{453.592}\ pounds=0.8017\ pounds$